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Version: 1.3.0


The function Set.remove creates a set containing the elements of a given set, without a given element. If the element is not already present, the new set is the same as the old one, as expected.

const my_set: set<int> = Set.literal(list([3, 2, 2, 1]));
const new_set = Set.remove(3, my_set);
const contains_3 = Set.mem(3, new_set); // == false

Note: See the predefined namespace Set